First, recognize that x is a factor of every term. This means the equation can be written as
x(x^2 - 6x + 7) = 0
Among other things, this means that x = 0 is a solution to the equation.
The quadratic term does not factor nicely, so the zeros of it can be found using the quadratic formula.
x = (-b±√(b^2-4ac))/(2a)
= (-(-6)±√((-6)^2 - 4*1*7))/(2*1)
= (6 ±√(36-28))/2
x = 3 ± √2 (These are the other two solutions.)
x(x^2 - 6x + 7) = 0
Among other things, this means that x = 0 is a solution to the equation.
The quadratic term does not factor nicely, so the zeros of it can be found using the quadratic formula.
x = (-b±√(b^2-4ac))/(2a)
= (-(-6)±√((-6)^2 - 4*1*7))/(2*1)
= (6 ±√(36-28))/2
x = 3 ± √2 (These are the other two solutions.)
