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How To Solve X^3-6x^2+7x=0?

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Oddman answered
First, recognize that x is a factor of every term. This means the equation can be written as
  x(x^2 - 6x + 7) = 0
Among other things, this means that x = 0 is a solution to the equation.
The quadratic term does not factor nicely, so the zeros of it can be found using the quadratic formula.
  x = (-b±√(b^2-4ac))/(2a)
  = (-(-6)±√((-6)^2 - 4*1*7))/(2*1)
  = (6 ±√(36-28))/2
  x = 3 ± √2    (These are the other two solutions.)

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