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How to solve x^2-25=0?

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xiao guguai Profile
xiao guguai answered
The solution is x=5 or -5.
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Anonymous answered
Here's how.  First add 25 to both sides of the equation:  X2 - 25 + 25 = 0 + 25 so you now have x2 = 25.  Now find the square roots of both sides of the equation, remembering that any squared number has positive and negative square roots:  (x2)1/2 = (25)1/2  So (after multiplying to eliminate exponents on the lefthand side) we have . . . X equals the positive or negative square root of 25  By definition the square of all non-imaginary numbers is a postive number, meaning, for instance, that both 5 squared and -5 squared equals 25 . . .  So the square roots of 25 must be each of positive 5 and negative 5, giving you the solution: X = +5, -5  So that is how . . .          . . . A round peg goes in a "squared" hole.

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