The solution is x=5 or -5.

Add twenty five to the other side of the equal sign and find the sqare route. X=5

Here's how. First add 25 to both sides of the equation: X

^{2}- 25 + 25 = 0 + 25 so you now have x^{2}= 25. Now find the square roots of both sides of the equation, remembering that any squared number has positive and negative square roots: (x^{2})^{1/2}= (25)^{1/2}So (after multiplying to eliminate exponents on the lefthand side) we have . . .__X equals the positive or negative square root of 25__By definition the square of all non-imaginary numbers is a postive number, meaning, for instance, that both 5 squared and -5 squared equals 25 . . . So the square roots of 25 must be each of positive 5 and negative 5, giving you the solution: X = +5, -5 So that is how . . . . . . A round peg goes in a "squared" hole.