Trying To Find A Degree Of A Triangle Using Trigonometry. Prob 1 A Triangle With Hyp=27 Bottom Leg=13 And Then The Side Leg Is Missing But It Wants To Know The Degree Of The Angle One Angle Is 90 Though And It Wants To Know The Degree Of The Lin?

Consider a right angle triangle ABC. The hypotenuse AC is equal to 27 and base AB is equal to 13. Then according to Pythagoras theorem;

AC² = AB² + BC²

BC²= AC² - AB²

BC²= 27² - 13²

BC²= 729 - 169

BC²= 560

BC= 23.66

Angle B is 90^o then angle A and angle C are;

CosA= AB/Ac

CosA=13/27

A= because^-1[13/27]

A= 61.22^o

As we know;

A + B + C = 180^o

61.2 + 90 + C=180

C= 28.78^o