X2-2x-6 How To Graph It?

If you use "completing the square" algorithm, the equation results in y=(x +1)^2 - 7; it's graph will be a "normal", up-opening parabola, whose vertex (lowest point) is at (-1, -7), intersecting the y-axis at (0, -6), and has a mirror reflection of all of its points, with x= -1 as axis of symmetry). You can get a good "sketchtimation" of the curve by finding the mirror image of (0, -6) across the axis of symmetry and guesstimating the rest of the curve from those 3 points. Your sketch should be close to the one the first responder suggested you plot using a table of values. There are two, symmetric intersections with the x-axis, but they are irrational numbers that are harder to plot unless you have a table of square roots: -1 + sqr rt of 7 ,and -1 - sq. Rt of 7.
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2x-4
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2x -9x=3x+6 . X=
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It would be
y = x^2 + 2x - 6

Assume a range of values for x (say -3 to +3). Put each value of x in the given equation to calculate the corresponding value of y.

Plot the resulting pairs of values on the graph.
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