If you use "completing the square" algorithm, the equation results in y=(x +1)^2 - 7; it's graph will be a "normal", up-opening parabola, whose vertex (lowest point) is at (-1, -7), intersecting the y-axis at (0, -6), and has a mirror reflection of all of its points, with x= -1 as axis of symmetry). You can get a good "sketchtimation" of the curve by finding the mirror image of (0, -6) across the axis of symmetry and guesstimating the rest of the curve from those 3 points. Your sketch should be close to the one the first responder suggested you plot using a table of values. There are two, symmetric intersections with the x-axis, but they are irrational numbers that are harder to plot unless you have a table of square roots: -1 + sqr rt of 7 ,and -1 - sq. Rt of 7.

2x-4

2x -9x=3x+6 . X=

It would be

y = x^2 + 2x - 6

Assume a range of values for x (say -3 to +3). Put each value of x in the given equation to calculate the corresponding value of y.

Plot the resulting pairs of values on the graph.

y = x^2 + 2x - 6

Assume a range of values for x (say -3 to +3). Put each value of x in the given equation to calculate the corresponding value of y.

Plot the resulting pairs of values on the graph.

1. Plot a graph of y= x2 + 2X +2x- 15 for (-66), by completing the table below.

X -6 -5 -4 -3 02 01 0 1 2 3 4 5 6

X2

2x

-15

y

X -6 -5 -4 -3 02 01 0 1 2 3 4 5 6

X2

2x

-15

y