There are a lots of solutions.!

i) Differentiate to find the gradient function of the tangent

dy/dx = e^x + xe^2 ........(1)

ii) Substitute x = 0 into (1) to find the slope of the tangent

slope of tangent m = e^(0) + (0)e^(0)

= 1

slope of normal = - 1

Equation of normal

y - 0 = -1(x - 0)

y = - x

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