There are a lots of solutions.!
i) Differentiate to find the gradient function of the tangent
dy/dx = e^x + xe^2 ........(1)
ii) Substitute x = 0 into (1) to find the slope of the tangent
slope of tangent m = e^(0) + (0)e^(0)
slope of normal = - 1
Equation of normal
y - 0 = -1(x - 0)
y = - x
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